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Chain, Product and Quotient Rule: Exercise 4

by Batool Akmal
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    Let?s have a look at our next example, we have y equals to 4x to the minus 2, 7 plus 3x to the minus 5. Observe and look at your function for a bit and decide what kind of function you see and what kind of method you would use now to differentiate it. Now you may think or you may have a look at it and see that there are actually a few different ways of writing it and then you have choice of using different rules. For example, I could take this x to the minus 2 down so I could write this as 4 over x squared and then 7 plus 3x to the minus 5. Let?s leave the x to the minus 5 there because it?s in the brackets just to not over complicate things. So this is the same as 4, 7 plus 3x to the minus 5, over x squared. You can see that both of these are the same functions. So this function here is exactly the same as this function, only rewritten and both of them will now need different methods for differentiation. So this function here is a function multiplied by another function, so u times v. However this function is a function that's being divided by another. Both of them would give you the same answer if you use the product rule here and if you use the quotient rule here. We should always just double check using the alternate method just to see that you?ve got the same answer. Now I personally feel that the product rule is always easier because it doesn?t have to divide by the v squared so I'm gonna go with the product rule and if there are ways in which you can convert your...

    About the Lecture

    The lecture Chain, Product and Quotient Rule: Exercise 4 by Batool Akmal is from the course Quotient Rule, Chain Rule and Product Rule.


    Author of lecture Chain, Product and Quotient Rule: Exercise 4

     Batool Akmal

    Batool Akmal


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