00:01
So we’ve just learned how to
integrate trig,
e of x's and ln of x's
I’m now going to show you some techniques
when functions become fairly complicated,
the things that we can do to simplify it.
00:15
In mathematics, there’s this
thing called substitution,
which we quite like when things
get a bit too complicated.
00:22
We can make it easier by making substitutions
dealing with shorter functions,
dealing with our own substitution and
then changing it back at the end.
00:31
It’s a very useful technique especially
when things get more complex.
00:35
So, what I mean by that is if
you have a function f of x dx,
and imagine it’s not
very straightforward,
it has two or three things multiplying
together, or some functions,
you can change this entire
function to a u function.
00:50
So the idea is that we change everything
in that function to u functions.
00:54
We then differentiate it with respect
to u rather than with respect to x,
but we also change the limits.
01:02
Now, this may look a bit bizarre
as to why should we do this.
01:05
You’ll see this is useful especially when
we do the more complicated functions.
01:10
It probably isn’t a good idea doing this
when your functions are straightforward
and you can just integrate.
01:15
Add one to the power and
divide by new power.
01:17
But you’ll see that the functions
were about to integrate.
01:20
It makes life a lot easier if
we use substitution methods.
01:25
Keep this definition in mind,
but I’ll teach you this by
using numerical examples
because it’s a lot easier and it makes a
lot of sense when we do it with functions.
01:37
So let’s look at this example.
01:38
We’re going to work through
this slowly because with it,
I’m going to teach you
integration by substitution.
01:45
So, our integral says that
we’ve got x multiplied by cos,
x squared plus 1 dx.
01:58
We also have the limits 0 and 1.
02:02
Now, if I asked you just to integrate
it, you probably won’t be able to
because it’s a function that’s being
multiplied with another function,
and we haven’t really spoken
about any techniques here.
02:12
So, we do need to find a way
to make this easier for us
in order for us to integrate it.
02:18
To do this, we use this
method called substitution.
02:21
So, anything that look too complicated, we
can substitute easier letters for them,
and we can change the whole
equation in terms of that letter.
02:30
We usually use the letter u.
02:33
So, here’s what I’m going to do.
02:34
I’m going to change this angle into
something a little bit easier.
02:38
So, I’m going to say here on the side,
let u equals to x squared plus 1.
02:44
So, this equation or this integral
now becomes x cos of u dx.
02:53
Now, it’s a very mixed
statement here.
02:56
There’s lots going on.
02:57
I’ve got an x, I’ve got a u, I’ve got a dx,
and I’ve got these limits
which are my x limits.
03:02
So be clear about those.
03:04
These are your x limits and they
can only go into x functions.
03:09
So, in some sense, I’ve made it a
little bit messier, but let’s continue.
03:13
I am now keeping a clear
objective that I want to
make this entire equation
in terms of u’s.
03:19
I want to change everything into u.
03:22
So the next step I’m going to start
with is changing my dx to du.
03:27
I can do that by using
my substitution here.
03:31
So, I said u was x squared plus 1.
03:35
I can now do du by dx.
03:36
I can differentiate
this to give me 2x.
03:40
I can get this dx by itself just
by rearranging this equation.
03:43
So I can write du
equals to 2x dx.
03:47
I’ve multiplied this
on the other side.
03:49
And remember, I want to
take this by itself,
so make this the subject of the equation
so I can rewrite this as
du over 2x equals to dx.
04:01
So hopefully, this is
straightforward enough.
04:02
I took my u substitution, I
differentiated du with dx,
and then I rearranged
to get dx by itself.
04:10
Why did I do it?
Because I can replace this
dx with this dx here.
04:16
So, watch what happens when I do this.
04:18
I do 1 0 x cos of u.
04:22
And instead of my dx, I
can now write du over 2x.
04:29
Still looks like a mixture,
but if you notice here, this
x is cancelling with this x.
04:36
Let’s see what our integral looks like now.
04:38
0 1 cos of u du.
04:43
And this I’m a lot happier with
because I know that cos of anything
integrated with respect to that thing
will give me a straightforward answer.
04:51
I know my identities.
04:54
There’s one little thing I
need to do here though.
04:57
Remember I said that these
were your x limits.
05:01
So, I need to change
those limits.
05:03
Those are my x limits and those
can’t go into this function
because this is all
in terms of u.
05:09
But again, I come back to my
substitution, u substitution.
05:14
I said u was x squared plus 1.
05:18
So, we want to know what u is
when x equals to 1 and when x equals
to 2 --
when x equals to 0, I mean.
05:29
So, you can find out u when we put
1 in; 1 squared plus 1 is just 2.
05:34
And when you put 0 in, that gives
you 0 squared plus 1 is just 1.
05:39
So, what you’ve done here is
you’ve changed your x limit;
x equals to 1, x equals to 0.
05:44
You’ve changed your x
limit to u equals to 2,
and your x limit of
0 to u equals to 1.
05:51
And now, if I change my limits,
remember, the 1 has become
2, and the 0 has become 1.
05:57
I have cos u du,
and life is a lot easier integrating
this as compared to the first function.
06:06
How did you integrate cos?
Remember the little tables that we did.
06:10
Sine goes to cos, cos goes to
-sine when you differentiate;
when you integrate,
you go backwards.
06:19
So cos, and if you look at this here,
we’re going in that direction here.
06:22
Cos will integrate to sine.
06:25
So, we now end up with sine u,
nice and easy integrated.
06:30
We have to put our limits in.
06:31
So we’ll put 1 and 2 in.
06:33
So, we can just leave it as is
because we’re not using calculators.
06:39
So the answer to this as a
statement is sine2 minus sine1.
06:45
And that here is your integral.
06:48
If you’re using calculators,
it’s just a simple job of you putting it
into your calculator to find your answer.