00:01
So if you enjoyed the proof for sin x,
now is your chance to take the lead on the proof for cos x.
00:07
It's very similar to what we've just done with the same methods.
00:10
It's incredible that we've learnt these derivatives all through school
but we've never really seen where they come from
and now is your chance to actually prove it to yourselves.
00:19
So, using exactly the same method, let's now find the derivative for cos x.
00:25
Remember, we kind of, not kind of we do know the answer to this already
but let's see if we can actually derive it algebraically.
00:32
So, once again using differentiation from first principles,
we are saying that dy/dx as the limit of delta x tends to zero is f of x plus delta x
minus f of x divided by delta x. This time, we are differentiating cos x
or we're finding what the derivative of cos x is.
00:54
So, that's what we're trying to do as the limit of delta x tends to zero.
00:59
So, we can rewrite this as cos x plus delta x minus the original cos x all over delta x.
01:09
This functional now, we will need to expand using our double angle
or addition law formulas that we gave right at the start.
01:19
So, remember that you can compare this with cos of a plus b.
01:24
So this is the same as cos of a plus b and you can look that rule up
and actually use that to expand cos x plus delta x.
01:33
So, if we expand this using our rule, we can say cos x cos delta x.
01:39
This time we have a minus sin x sin delta x minus cos x over delta x
is our differentiation from first principles. Again, we can now combine our cos x terms.
01:56
So you have a cos x value here and a cos x value here.
01:59
So we can just rewrite it in order to write them next to each other so it doesn't look too confusing.
02:04
So we have cos x delta x minus cos x and then you also have minus sin x sin delta x.
02:13
And don't forget that this is all over delta x.
02:19
The reason we've done that is so we can rewrite it as a common factor.
02:24
So you can take cos x out of the first 2 terms. So, those 2 terms there,
leaving you with cos of delta x minus 1 over delta x, and then you can take sin x out,
leaving you with sin delta x over delta x. And again, don't forget, right at the start
we said that the limit of delta x should tend to zero.
02:53
So for each part we can now apply it to each individual,
let's just put delta x here so we can follow what we're saying.
03:04
So for each individual section of this equation, we now apply delta x equals to zero.
03:09
Let's do that. Cos x isn't really affected because there's no delta x there. So, we have cos x.
03:14
This if you remember from the previous proof that cos of delta x as delta x tends to zero,
this goes to 1. Okay? Because cos of, as you get closer and closer to zero is 1.
03:27
So, 1 minus 1 gives you zero. So this entire term becomes zero.
03:31
Here, we have minus sin x which isn't affected by delta x and remember again,
from our very first statement on one of the properties that we mentioned earlier,
that sin x over x as the limit of x tends to zero is 1.
03:46
Our x in this case is delta x, so it's the same thing, it's still 1.
03:50
So that multiples with 1 and eventually, we can now say that dy/dx of this function is minus sin x
and here we have derived the differential or the standard differential answer to cos of x.
04:06
So we said at the beginning that cos of x equals to minus sin x and we've proven now.